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3a^2+27a+24=0
a = 3; b = 27; c = +24;
Δ = b2-4ac
Δ = 272-4·3·24
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-21}{2*3}=\frac{-48}{6} =-8 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+21}{2*3}=\frac{-6}{6} =-1 $
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